Question

The nuclear radius of ${}_4{Be}^8$ nucleus is :

• A. $1.3\times {10}^{-15}m$
• B. $2.6\times {10}^{-15}m$
• C. $1.3\times {10}^{-13}m$
• D. $2.6\times {10}^{-13}m$

Answer 1

Answer: (B)

$2.6\times {10}^{-15}m$

Mass number of ${}_{4}B{e}^8$ $A=8$

Nuclear radius, $R=R_o{A}^{1/3}$ where $R_o=1.3\times {10}^{-15}m$

$\therefore$ $R=1.3\times {10}^{-15}\times 8^{1/3}$ $m$

$⟹$ $R=1.3\times {10}^{-15}\times 2=2.6\times {10}^{-15}m$