Question

The nuclear reaction ${}_{48}{\text{Cd}}^{107}\to {}_{47}{\text{Ag}}^{107}$ can occur with the

• A. $\alpha$ $\text{decay}$
• B. ${\beta }^{-}$ $\text{decay}$
• C. $\text{Proton emission}$
• D. $\text{Electron capture}$

Answer 1

The correct option is D $\text{Electron capture}$

As there is decrease in $Z$ by $1$ and no change in $A$.

So, conversion of a proton to a neutron inside the nucleus should have taken place.

This process occurs by ${\beta }^{+}$ decay or electron capture.

The electron capture is represented by,

$p+{}_{-1}{e}^0\to n+\overline{\nu }$

Hence, option $\left(D\right)$ is correct.

Why this Question? To give an idea about electron capture.