No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
isobars
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
isotones
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
isomers
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C isotones Number of neutrons present in 13Al27=27−13=14 Number of neutrons present in 14Si28=28−14=14 Since, elements which have equal number of neutrons are called as isotones, so 13Al27 and 14Si28 are isotones of each other.