The nucleophilic addition at the carbonyl carbon changes its hybridization fromto

s p

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s p^{2}

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s p^{3}

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s p^{3} d

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Solution

The correct option is C $s p^{3}$
Carbonyl carbons are planar and $s p^{2}$ hybridized. When a nucleophile adds to the carbonyl carbon, its leads to the formation of a tetrahedral intermediate which is $s p^{3}$ hybridized.

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Similar questions

In the nucleophilic addition of CN^- to carbonyl carbon, the intermediate formed is

Q. Choose the correct order of alkyl group attached to aldehyde that prefer the nucleophilic addition at carbonyl carbon?

Q. With in each set, select the compound which is more reactive to nucleophilic addition at carbonyl carbon.

(I) C H_{3} C O C H_{2} C H_{2} B r o r C H_{3} C O C H_{2} B r

(I I) C H_{3} C H O o r C H_{3} C O C H_{3}

(I I I) C H_{3} C O C H_{3} o r C H_{3} C O C F_{3}

(I V) P h C H O o r C H_{3} C H O

Q. Statement- I: Carbonyl compounds take part in nucleophilic addition reactions.
Statement- II: These reactions are initiated by nucelophilic attack at the electron deficient carbon atom.

The most characteristic reaction of aldehyde and ketones is nucleophilic addition to carbon oxygen double bond. Aldehyde and ketones are easily susceptible to nucleophilic addition because of structural features. The trigonal planar arrangement of groups around the carbonyl carbon atom means that the carbonyl carbon atom is relatively open to attack from above and below the plane of carbonyl group. The partial positive charge on the carbonyl atom means that it is especially susceptible to attack by a nucleophile

Aldehyde reacts with $2^{\circ}$ amines to form

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The nucleophilic addition at the carbonyl carbon changes its hybridization fromto

The correct option is C sp3Carbonyl carbons are planar and sp2 hybridized. When a nucleophile adds to the carbonyl carbon, its leads to the formation of a tetrahedral intermediate which is sp3 hybridized.

The correct option is C $s p^{3}$
Carbonyl carbons are planar and $s p^{2}$ hybridized. When a nucleophile adds to the carbonyl carbon, its leads to the formation of a tetrahedral intermediate which is $s p^{3}$ hybridized.