Question

The nucleus ${}_{48}{\text{Cd}}^{115}$, after the emission two successive negative $\beta$ -particles, changes to

• A. ${}_{49}{\text{Sn}}^{114}$
• B. ${}_{50}{\text{Sn}}^{113}$
• C. ${}_{46}{\text{Pa}}^{115}$
• D. ${}_{50}{\text{Sn}}^{115}$

Answer 1

The correct option is D ${}_{50}{\text{Sn}}^{115}$

Emission of beta negative particle decay a neutron into a proton (increases atomic number by 1),electron and electron antineutrino ,but mass number remains same. So tow beta negative particle will increase atomic number by 2

and ${}_{48}^{115}Cd$ will convert to ${}_{50}^{115}Sn$