Question

The nucleus ${}_6{C}^{12}$ absorbs an energetic neutron and emits a beta particle( $\beta$ ).The resulting nucleus is

• A. ${}_7{N}^{14}$
• B. ${}_5{B}^{13}$
• C. ${}_7{N}^{13}$
• D. ${}_6{C}^{13}$

Answer 1

Answer: (C)

${}_7{N}^{13}$

${}_6{C}^{12}{+}_0^{1}n{\to }_{-1}^{0}e{+}_Z^{A}X$

Mass balance: $A+0=12+1$

$A=13$

Charge balance: $6+0=-1+Z$

$Z=7$

$i.e.X={}_7^{13}N$