The nuclide 5021Sc, mass 49.9516 amu, is neutron rich. It decays to form 5022Ti, mass 49.94479 amu. If the emitted β−particle has a kinetic energy of 0.80 MeV; what is the kinetic energy of the neutrino emitted simultaneously?
A
5.54 MeV
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B
6.54 MeV
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C
9.54 MeV
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D
None of these
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Solution
The correct option is A 5.54 MeV Mass defect =49.9516−49.94479 =6.81×10−3amu Binding energy =6.81×10−3×931MeV =6.34011MeV Kinetic energy of the emitted β− particle = 0.80 V ∴ Kinetic energy of the neutrino emitted = 5.54 MeV