Question

The nuclide which disintegrates by emitting a $\beta$ - particle to form ${}_7^{14}$N contains:

• A. $8$ neutrons
• B. $10$ neutrons
• C. $7$ neutrons
• D. $6$ neutrons.

Answer 1

Answer: (A)

$8$ neutrons

${}_Z^{A}X{\to }_{-1}^{0}e{+}_7^{14}N$

$A=14$

$Z=-1+7$ $=6$

No. of neutrons $=14-6$ $=8$