The number (1+√3)2 is a/an
Irrational Number
On expanding (1+√3)2 using the formula (a+b)2, we find that
(1+√3)2=(1)2+(√3)2+2(1)(√3)=4+2√3
which is the sum of a rational term, 4 and an irrational term 2√3.
Therefore, the equation (1+√3)2 is also irrational.