Applying Difference of Squares as a Product of Its Sum and Difference
The number ...
Question
The number 101100−1 is divisible by
A
100
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B
1000
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C
10000
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D
100000
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Solution
The correct options are A100 B1000 C10000 (101)100−1 =(1+100)100−1 =1+100C1100+100C21002‘+...100C100100100−1 =100C1100+100C21002‘+...100C100100100 =1002+1002∗99+... =1002[1+m] where m is a positive integer.