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B
5 and 11
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C
3 and 9
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D
3 and 11
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Solution
The correct option is D 3 and 11 The number 111111111111is divisible by 3 ∵1+1+1+1+1+1+1+1+1+1+1+1=12 12 is divisible by 3 so the number 111, 111, 111, 111, is divisible by 3 The number 111,111,111,111,is divisible by 11 because the difference of the sums of alternating digits is 0