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Question

The number 916238457 is an example of nine digit number which contains each of the digit 1 to 9 exactly once. It also has the property that the digits 1 to 5 occur in their natural order, while the digits 1 in 6 do not. Number of such numbers are

A
2268
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B
2520
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C
2975
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D
1560
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Solution

The correct option is B 2520

The required conditions to be satisfied are,

i) the number must be 9 digit number containing 1 to 9 digits once

ii) digits 1 to 5 must occur in consecutive order

iii) digits 1 to 6 must not occur in consecutive order

So, condition (i) is fulfilled in only one way. So, places of 1 to 5 are fixed in the number.

Now, we have 5 digits and 6 places (_1_2_3_4_5_)

Now, we can place 6 in any of the first 5 places. Therefore, total number of ways to do it is 5.

Similarly, following the same to place 7, 8 and 9, we have 7, 8 and 9 places respectively.

Therefore, by multiplication rule of counting, we have

1×5×7×8×9=2520 number of ways

Hence, this is the required result.


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