The number $a_{n} = 6^{n} - 5 n$ for $n = 1, 2, 3, . . . .$ when divided by $25$ leave the remainder

9

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Solution

The correct option is D $1$
Given that,

$a n = 6^{n} - 5 n$

For $n = 1, 2, 3, 4.......$

thus, $a_{1} = 6^{1} - 5 \times 1 = 1$

$a_{2} = 6^{2} - 5 \times 2 = 26$

$a_{3} = 6^{3} - 5 \times 3 = 501$

$a_{4} = . . . . .$

when divided by $25$

then, the reminder $= 1$

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