Question

The number average molecular weight (${\stackrel{-}{M}}_n$) of Teflon polymer is $120,000g/mol$. Find the Degree of polymerization.

Answer 1

Given,

number average molecular weight (${\stackrel{-}{M}}_n$)$=120,000g/mol$

The given polymer is Teflon.

In Teflon, the monomer used is $C{F}_2-C{F}_2$.

The molecular mass of $C{F}_2-C{F}_2$ is $M_o=100g/mol$

The Degree of polymerization is given as$=\frac{{\stackrel{-}{M}}_w}{M_o}=\frac{120000}{100}=1200$