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Standard X

Physics

Ohm's Law

The number de...

Question

The number density of electron in copper is 8.5 × 10²⁸ m^-3. What is the current flowing through a copper wire of length 0.2 m, area of cross-section 1 mm² when connected to a battery of 4.0 V? Given that electron mobility = 4.5 × 10^-6 m²V^-1s^-1 and charge on the electron is 1.6 × 10^-19 C.

1.12 A

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1.29 A

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1.22 A

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1.17 A

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Solution

The correct option is B (1.22 A)
$I = n e A v_{d} = n e a μ \frac{V}{l}$
by substituting the value in above equation we get
$I = 8.5 \times 10^{28} \times 1.6 \times 10^{- 19} \times 10^{- 6} \times 4.5 \times 10^{- 6} \times \frac{4}{0.2} = 1.22 A$
Hence final answer is 1.22A

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Similar questions

Q. Find the current flows through a copper wire of length 0.2 m, area of cross-section

1 m m^{2}

, when connected to a battery of 4V. Given that electron mobility is

4.5 \times 10^{-} 6 m^{2} s^{-} 1

and charge on an electron is

1.6 \times 10^{- 19} C

The number density of electron in copper wire is

8.5 \times 10^{2} 8 m^{3}

A copper wire has a cross sectional area of $1 m m^{2}$ . The electron density of copper is $8.5 \times 10^{28} m^{3}$ . Calculate the mean drift velocity of the electrons through the wire when the current is 3 A.

Q. Drift speed of electrons, when

1.5 A

of current flows in a copper wire of cross section

5 m m 2

, is

v

. If the electron density in copper is

9 \times 10^{28} / m^{3}

the value of

v

m m / s

is close to (Take charge of electron to be

= 1.6 \times 10^{- 19} C

)

Q. Drift speed of electrons, when

1.5 A

of current flows in a copper wire of cross-section

5 {mm}^{2}

, is

v

. If the electron density in copper is

9 \times 10^{28} m^{- 3}

the value of

v

{mm s}^{- 1}

close to

(Take charge of electron to be = 1.6 \times 10^{- 19} C

)

Q. A current of

1 A

flows through a copper wire. The number of electrons passing through any cross-section of the wire in

1.6 s e c

is (charge of a electrons

= 1.6 \times 10^{- 19} C

)

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The number density of electron in copper is 8.5 × 1028 m-3. What is the current flowing through a copper wire of length 0.2 m, area of cross-section 1 mm2 when connected to a battery of 4.0 V? Given that electron mobility = 4.5 × 10-6 m2V-1s-1 and charge on the electron is 1.6 × 10-19 C.

The correct option is B (1.22 A)I=neAvd=neaμVl by substituting the value in above equation we getI=8.5×1028×1.6×10−19×10−6×4.5×10−6×40.2=1.22AHence final answer is 1.22A

The correct option is B (1.22 A)
$I = n e A v_{d} = n e a μ \frac{V}{l}$
by substituting the value in above equation we get
$I = 8.5 \times 10^{28} \times 1.6 \times 10^{- 19} \times 10^{- 6} \times 4.5 \times 10^{- 6} \times \frac{4}{0.2} = 1.22 A$
Hence final answer is 1.22A