The number obtained by interchanging the digits of a two-digit number is more than the original number by 36 and the sum of the digits is 12. What is sum of the original and interchanged number?

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132

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None of these

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Solution

The correct option is C
132

x+y = 12, 10y+x - (10x+y) = 36.

On calculating we get x=4 & y=8.

Thus, sum = 48+84 = 132

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The number obtained by interchanging the digits of a two-digit number is more than the original number by 36 and the sum of the digits is 12. What is sum of the original and interchanged number?

The correct option is C 132 x+y = 12, 10y+x - (10x+y) = 36. On calculating we get x=4 & y=8. Thus, sum = 48+84 = 132

The correct option is C
132

x+y = 12, 10y+x - (10x+y) = 36.

On calculating we get x=4 & y=8.

Thus, sum = 48+84 = 132