Question

The number of 3-digit even numbers that can be formed from the digits 0, 1, 2, 3, 4 and 5, repetition of digits being not allowed, is

• A. 60
• B. 56
• C. 52
• D. 48

Answer 1

Answer: (A)

60

Solution:

We have, digits $0,1,2,3,4$ and $5$

Even numbers-

(i) when $0$ is at unit place, then

There are $5$ ways to fill 10's place and $4$ ways to fill 100's place

So, no. of ways $=4\times 5=20$

(ii) when $0$ is not at unit place, then

There are $2$ ways to fill unit's place, $5$ ways to fill 10's place and $4$ ways to fill 100's place

So, no. of ways $=2\times 5\times 4=40$

$2$ or $4$

$\therefore$ total number of even numbers $40+20=60$

Hence, A is the correct answer.