The number of 5 digit numbers thathat can be formed using the digits 0,1,2,3,4,5 that are divisible by 6 when repetition is not allowed?
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Solution
The last digits can only be 0,2,4 to be divisible by 6.
(i) with out 0 and last digit either 2 or 4 is 2×4!=482×4!=48 (ii) with 0 as last digit and without 3, the number as 4!=244!=24 (iii) with 2 or 4 as last digit and without 3 numbers are 3636 ∴∴ Total no of ways = 108 Answer : 108