Question

The number of $6$-digit numbers that can be made with the digits $0,1,2,3,4$ and $5$ so that even digits occupy odd places, is

• A. $24$
• B. $36$
• C. $48$
• D. $noneofthese$

Answer 1

Answer: (A)

$24$

The odd places are occupied by even numbers i.e., $0,2,4$
There are 3 places so total $=3!$ ways $=6$ ways
Now it should be a 6 digit number so the first digit can't be 0
So, we rule out 2 options
$=6-2=4$ ways

For the even places any of the 3 odd numbers can occupy in $3!$ ways $=6$ ways

Total $=4.6$ ways $=24$ ways