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Question

The number of 6 digits numbers that can be formed from the digits 1,2,3,4,5,6,&7 so that digits do not repeat and the terminal digits are even is :

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Solution

If 1 select & even digit as terminal digit, 1 can choose the remaining 5 numbers out of 6 in 6 ways & arrange them in 5! ways i.e., 120 ways. Therefore, when even terminal digit I have 6×120=720. Therefore, for 3 even terminal digits I have 3×720=2160.

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