Question

The number of 6’s present in the quotient obtained when 111…..111 (99 number of 1’s) is divided by 33……3(33 number of 3’s) is

• A. 35
• B. 32
• C. 33
• D. 34

Answer 1

The correct option is B

32

3 $\times$ 37 = 111

33 $\times$ 3367 = 111111

So the pattern is if the number of 1’s on R.H.S is n then the number of 3’s and 6’s in each term on L.H.S is $\left(\frac{n}{3}\right)and\left(\frac{n}{3}\right)-1$ respectively.