Let the denominator be x
then, numerator = x-6
according to question ,
=> (x-6)+3/x = 2/3
=> (x-6+3)/x = 2/3
=> (x-3)/x = 2/3
=> 3(x-3) = 2x
=> 3x-9 = 2x
=> 3x-2x = 9
=> x = 9. (denominator)
numerator = x-6 => 9-6 = 3
then , fraction = 3/9
Simplest way
let the denominator=x,numerator=x-6
given-if 3 is added to numerator the fraction becomes 2/3
x-6+3/x=2/3
x-3/x=2/3
3(x-3)=2x
3x-9=2x
3x-2x=9
x=9
numerator=9-6=3
the original fraction=3/9