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Question

The number of A in TP such that the trace of A is not divisible by p but det (A) is divisible by p is [Note: The trace of a matrix is the sum of its diagonal entries.]

A
(p1)(p2p+1)
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B
p3(p1)2
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C
(p1)2
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D
(p1)(p22)
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Solution

The correct option is C (p1)2
Trace of A=2a will be divisible by p iff a=0
|A|=a2bc
for (a2bc) to be divisible by (p1) ordered pairs (b,c) for any value of A
Required no. is (p1)2
Option C

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