Question

The number of accidents occurring in a plant in a month follows Poisson distribution with mean as 5.2. The probability of occurrence of less than 2 accidents in the plant during a randomly selected month is

• A. 0.029
• B. 0.034
• C. 0.039
• D. 0.044

Answer 1

The correct option is B 0.034

$P(x<2)=P\left(0\right)+P\left(1\right)$

$=\frac{e^{-\lambda }{\lambda }^0}{0!}+\frac{e^{-\lambda }{\lambda }^1}{1!}$

$=e^{-5.2}(1+5.2)$

= 0.0055 × 6.2

$P(x<2)=0.0342$