The number of alkenyl groups possible (structural isomers) from $C_{4} H_{7} -$ are:

7

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5

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3

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8

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Solution

The correct option is C $5$
Following five alkenyl groups are possible from $- C_{4} H_{7}$ on the basis of structural isomerism.

(i) $C H_{3} - C H_{2} - C H = C H -$
(ii) $C H_{3} - C H = C H - C H_{2} -$
(iii) $C H_{2} = C H - C H_{2} - C H_{2} -$
(iv) $C H_{3} - C | = C H_{3} C H -$
(v) $C H_{3} - C | = C H_{2} - C H_{2}$

Branched isomers are shown in the image.

Option B is correct.

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