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Stereoisomerism

The number of...

Question

The number of all the possible stereoisomers formed by the given compound is:

A

2

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B

3

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C

32

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D

64

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Solution

The correct option is C 2
It has $2$ chiral centre and plane of symmetry.
Therefore, stereoisomers $= 2^{n - 1}$ [ $n =$ total chiral centre]
$= 2^{2 - 1} = 2^{1} = 2$
So the correct answer is '2'.

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