Question

The number of $\alpha$ and $\beta$ - particles emitted in the nuclear reaction ${}_{92}{U}^{238}{\to }_{90}T{h}^{234}{\to }_{91}P{a}^{234}$ are respectively:

• A. 1 and 1
• B. 1 and 2
• C. 2 and 1
• D. 2 and 2

Answer 1

Answer: (A)

1 and 1

${}_{92}{U}^{238}{\to }_{90}T{h}^{234}{\to }_{91}P{a}^{234}$

No. of $\alpha$-particle $=\frac{238-234}{4}=\frac{4}{4}=1$

No. of $\beta$-particle $=91-90=1$