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Byju's Answer
Standard XII
Mathematics
Ordered Pair
The number of...
Question
The number of
α
and
β
particles lost when
238
92
U
changes to
206
82
P
b
are:
A
8
α
,
6
β
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B
6
α
,
8
β
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C
6
α
,
6
β
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D
8
α
,
8
β
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Solution
The correct option is
A
8
α
,
6
β
Suggest Corrections
0
Similar questions
Q.
Match the following:
List-I
Series
List-II
Particles emitted
(
A
)
Thorium
(
i
)
8
α
,
5
β
(
B
)
Neptunium
(
i
i
)
8
α
,
6
β
(
C
)
Actinium
(
i
i
i
)
6
α
,
4
β
(
D
)
Uranium
(
i
v
)
7
α
,
4
β
Q.
A radioactive reaction is
92
U
238
→
82
P
b
206
. How many
α
and
β
particles are emitted
Q.
If the tangent to the curve
y
=
x
x
2
−
3
,
x
∈
R
,
(
x
≠
±
√
3
,
)
at a point
(
α
,
β
)
≠
(
0
,
0
)
on it is parallel to the line
2
x
+
6
y
−
11
=
0
,
then :
Q.
The number of
α
and
β
−
emitted during the radioactive decay chain starting from
226
88
R
a
and ending at
206
82
P
b
is
Q.
92
U
238
emits
8
α
−
particles and
6
β
−
particles. The neutron / proton ratio in the product nucleus is:
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