Question

The number of arrangements of the letters of the word 'BANANA' in which the two $Ns$ do not appear adjacently is

• A. $40$
• B. $60$
• C. $80$
• D. $100$

Answer 1

The correct option is A $40$

Total number of ways of arranging the letters of the word BANANA is $\frac{6!}{2!3!}=60$.
Number of words in which $2N^{\prime }s$ come together is $5!/3!=20$.
Hence, the required number is $60-20=40$.