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Question

The number of arrangements of the word "DELHI" in which E precedes 1 is


A

30

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B

60

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C

120

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D

59

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Solution

The correct option is B

60


There are 4 cases where E precedes 1 i.e.

Case 1: When E and I are together, which are possible in 4 ways whereas other 3 letters are arranged in 3!,

So, the number of arrangement

= 4×3!=24

Case 2: When E and I have 1 letter in between, which are possible in 3 ways whereas other 3 letters are arranged in 3!,

So, the number of arrangements

= 3×3!=18

Case 3: When E and I have 2 letteres inbetween, which are possible in 2 ways whereas other 3 letters are arranged in 3!

So, the number of arrangements

= 2×3!=12

Case 4: When E and I and have 3 letters in between, which are possible in 1 way whereas other 3 letters are arranged in 3!

So, the number of arrangements

= 1×3!=16

Thus, total number of arrangements

= 24+18+12+6 = 60


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