The number of atoms in $0.004$ g of Mg will be:

4 \times 10^{20}

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8 \times 10^{20}

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10^{20}

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6.02 \times 10^{20}

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Solution

The correct option is D $10^{20}$
$N o . o f a t o m s$ $= \frac{W e i g h t}{G r a m a t o m i c w e i g h t} \times N_{A}$
$= \frac{0.004}{24} \times 6 \times 10^{23}$

$= 10^{20} a t o m s$

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\frac{10^{22} + 10^{20}}{10^{20}}

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The value of $\frac{10^{22} + 10^{20}}{10^{20}}$ is
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(c) 101
(d) $10^{22}$

3.01 \times 10^{20}

98 mg

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