Question

The number of atoms in 0.1 mol triatomic gas is: ( $N_A=6.02\times {10}^{23}mo{l}^{-1}$ )

• A. $6.026\times {10}^{22}$
• B. $1.806\times {10}^{23}$
• C. $3.6\times {10}^{23}$
• D. $1.8\times {10}^{22}$

Answer 1

The correct option is B $1.806\times {10}^{23}$

1 mol of triatonic gas has 3 $\times 6.02\times {10}^{23}$ atoms

Therefore, no. of atoms i 0.1 mol $=0.1\times$ 3 $\times 6.02\times {10}^{23}$

$=1.806\times {10}^{23}$