Question

The number of atoms in 0.1 mole of a tetra atomic gas is:

$Given:(N_A=6.02\times {10}^{23}mo{l}^{-1})$

• A. $2.4\times {10}^{22}$
• B. $6.026\times {10}^{22}$
• C. $2.4\times {10}^{23}$
• D. $3.600\times {10}^{23}$

Answer 1

The correct option is C $2.4\times {10}^{23}$

According to formula

no. of moles $=\frac{No.ofatoms}{N_A}$

$1$ mol of atom contain $6.02\times {10}^{23}$ atoms

Hence,

$0.1$ mol of tetraatomic gas contain $=0.1\times 4\times 6.02\times {10}^{23}$

$=2.4\times {10}^{23}$ atoms.