Question

The number of atoms in $0.1$ mole of a triatomic gas is:

$(N_A=6.02\times {10}^{23})$

• A. $1.800\times {10}^{22}$
• B. $6.026\times {10}^{22}$
• C. $1.800\times {10}^{23}$
• D. $3.600\times {10}^{23}$

Answer 1

The correct option is C $1.800\times {10}^{23}$

A molecule of triatomic gas contains $3$ atoms.

Given number of moles of gas= $0.1$

$\therefore$ Moles of atoms= $3\times 0.1$

$1$ mole contains $6.02\times {10}^{23}$ atoms

$\therefore$ Number of atoms in given gas sample= $3\times 0.1\times 6.02\times {10}^{23}=1.800\times {10}^{23}$ atoms