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Question

# The number of atoms in 2.4 g of a body centred cubic crystal with edge length 200 pm is (density=10 gcm−3,NA=6×1023 atoms/mol)

A
6×1022
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B
6×1020
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C
6×1023
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D
6×1019
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Solution

## The correct option is A 6×1022Volume of unit cell = (200pm)3 ⇒(200×10−10cm)3 ⇒8×10−24cm3 Volume of 2.4 g of the element =MassDensity ⇒2.410⇒0.24 cm3 Number of unit cells =Total volumeVolume of a unit cell ⇒0.24cm38×10−24cm3 ⇒0.03×1024 For a bcc structure, number of atom per unit cell = 2 Number of atoms present in 2.4g = Number of atoms per unit cell × Number of unit cells ⇒2×0.03×1024 ⇒6×1022

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