The number of atoms in 20 g of SO3 is approximately-a- 1 x 1023-b- 1-5 x 1023-c- 2 x 1023-d- 6 x 1023

Moles present in 20 g of SO3 = 20/ 80.07 = 0.2498 mol Number of nbsp;molecules = 0.2498 nbsp;X nbsp;6.022 nbsp;X 1023 nbsp;= 1.5 X 1023 molecule ...

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The number of...

Question

The number of atoms in 20 g of SO₃ is approximately
(a) 1 x 10²³
(b) 1.5 x 10²³
(c) 2 x 10²³
(d) 6 x 10²³

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The number of atoms present in 4.25 g of $({NH}_{3})$ is approximately.

a) $1 \times 10^{23}$

b) $1.5 \times 10^{23}$

c) $0.25 \times 10^{23}$

d) $6.02 \times 10^{23}$

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6.02 \times 10^{23}

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