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Question

The number of atoms in 4.25 g of NH3 is approximately

A
1×1023
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B
2×1023
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C
4×1023
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D
6×1023
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Solution

The correct option is D 6×1023
17gmNH3 contains 6×1023 molecules of NH3
4.25 gmNH3 contains =6×102317×4.25
No. of atoms =6×1023×4.2517×4=6×1023

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