Question

The number of atoms in 4.25 g of $N{H}_3$ is approximately

• A. $1\times {10}^{23}$
• B. $2\times {10}^{23}$
• C. $4\times {10}^{23}$
• D. $6\times {10}^{23}$

Answer 1

The correct option is D $6\times {10}^{23}$

$\because 17gmN{H}_3$ contains $6\times {10}^{23}$ molecules of $N{H}_3$
$\therefore 4.25gmN{H}_3$ contains $=\frac{6\times {10}^{23}}{17}\times 4.25$
$\therefore$ No. of atoms $=\frac{6\times {10}^{23}\times 4.25}{17}\times 4=6\times {10}^{23}$