Question

The number of atoms present in 0.1 mole of p_{​​​​​​4 is}

Answer 1

The number of molecules = number of moles × Avogadro's constant.

no of molecules = $0.1\times 6.022\times {10}^{23}$
$6.022\times {10}^{22}$
=
in $P_4$ molecule-
no of atoms =$4\times numberofmolecules$

So,
no of atoms = $4\times 6.022\times {10}^{22}$

= $24.092\times {10}^{22}$