The number of beats produced per second by two tuning forks when sounded together is 4. One of them has a frequency of 250 Hz. The frequency of the other cannot be more than
A
250 Hz
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B
254 Hz
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C
246 Hz
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D
248 Hz
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Solution
The correct option is B 254 Hz The frequency of beats is |νa−νb|=4 Hence, the frequency of one fork is either 4 Hz more i.e. 254 Hz or 4 Hz less i.e. 246 Hz than the other one i.e. 250 Hz.
Since, the number of beats i.e. the frequency difference between two forks is 4, hence the frequency of another fork cannot be more than 254 Hz.