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Standard XII

Physics

Beat Frequency

The number of...

Question

The number of beats produces per second by two tuning forks when sounded together is $4$ . One of them has frequency of $250 H z$ . The frequency of the other cannot be less than

254 H z

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252 H z

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248 H z

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246 H z

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Solution

The correct option is B $246 H z$
Let the frequencies of two forks are $f_{1}$ , and $f_{2}$ ,
say $f_{1} = 250 H z$ and the beating freq between two is $4 H z$ , then

the possible frequencies of the fork 2, will be,

$f_{2} = 250 + 4 = 254 H z$ or $f_{2} = 250 - 4 = 246 H z$
so minimum possible frequency for fork 2 is $246 H z$ .
Option "D" is correct.

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The number of beats produces per second by two tuning forks when sounded together is 4. One of them has frequency of 250Hz. The frequency of the other cannot be less than

The correct option is B 246 HzLet the frequencies of two forks are f1, and f2, say f1=250Hz and the beating freq between two is 4Hz , then the possible frequencies of the fork 2, will be, f2=250+4=254Hz or f2=250−4=246Hzso minimum possible frequency for fork 2 is 246Hz.Option "D" is correct.

The number of beats produces per second by two tuning forks when sounded together is $4$ . One of them has frequency of $250 H z$ . The frequency of the other cannot be less than