Question

The number of bond pairs and lone pairs in $H_{2}O$ are _____ & _____ respectively.

• A. 2,1
• B. 2,0
• C. 4,0
• D. 2,2

Answer 1

The correct option is D

2,2

Lets first, find the number of electron pairs using VSEPR Theory.

Now, ep = $\frac{(V+L+A-C)}{2}$

Central atom $\to$ O [Least in number]

Number of Ligands $\to$ 2 valance electrons = 6

Now, ep = $\frac{(6+2)}{2}$ = 4

Therefore, number of electron pairs = 4

Number of Ligands = 2