Question

The number of carbon atoms present in $2.8$ gms of carbon monoxide is:

• A. $3.01\times {10}^{23}$
• B. $3.0\times {10}^{22}$
• C. $6.02\times {10}^{23}$
• D. $6.02\times {10}^{22}$

Answer 1

The correct option is D $6.02\times {10}^{22}$

Molecular weight of carbon monoxide is $28$ g, therefore, $2.8$ g is equal to $0.1$ mole of CO.

So, $0.1$ mole of carbon is present in $0.1$ mole of carbon monoxide.

Thus, number of atoms of carbon= $0.1\times 6.02\times {10}^{23}=6.02\times {10}^{22}$.