The number of carbon atoms present in a signature, if a signature written by carbon pencil weights $1.2 \times 10^{- 3}$ g is:

12.04 \times 10^{20}

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6.02 \times 10^{19}

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3.01 \times 10^{19}

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6.02 \times 10^{20}

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Solution

The correct option is B $6.02 \times 10^{19}$
No. of carbon atoms = $(\frac{1.2 \times 10^{- 3}}{12}) \times N_{A} = 6.02 \times 10^{19}$

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Similar questions

The number of carbon atoms present in a signature, if a signature written by carbon pencil weights $1.2 \times 10^{- 3}$ g is:

Q. The number of carbon atoms present in a signature, if a signature written by carbon pencil weights

1.2 \times 10^{- 3} g

Q. A signature, written in carbon pencil weighs

1 m g

. What is the number of carbon atoms present in the signature?

The number of carbon atoms present in a signature, if a signature written by carbon pencil weighs $1.2 \times 10^{- 3}$ g is:

A student puts his signature with a graphite pencil. If the mass of carbon in the signature is $10^{12}$ g, calculate the number of carbon atoms in the signature.

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The number of carbon atoms present in a signature, if a signature written by carbon pencil weights 1.2×10−3 g is:

The correct option is B 6.02×1019No. of carbon atoms = (1.2×10−312)×NA=6.02×1019

The number of carbon atoms present in a signature, if a signature written by carbon pencil weights $1.2 \times 10^{- 3}$ g is:

The correct option is B $6.02 \times 10^{19}$
No. of carbon atoms = $(\frac{1.2 \times 10^{- 3}}{12}) \times N_{A} = 6.02 \times 10^{19}$