The number of carbon atoms present in a signature, if a signature written by carbon pencil weighs $1.2 \times 10^{- 3}$ g is:

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Solution

The correct option is B
Atomic weight of Carbon = 12 g

12 g of carbon contain $6.023 \times 10^{23}$ number of atoms.

No. of carbon atoms present in $1.2 \times 10^{- 3}$ g of carbon = $\frac{1.2 \times 10^{- 3}}{12}$ $\times 6.023 \times 10^{23}$ = $\times 6.023 \times 10^{19}$

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The number of carbon atoms present in a signature, if a signature written by carbon pencil weighs 1.2×10−3 g is:

The correct option is B Atomic weight of Carbon = 12 g 12 g of carbon contain 6.023×1023 number of atoms. No. of carbon atoms present in 1.2×10−3 g of carbon = 1.2×10−312 ×6.023×1023 = ×6.023×1019

The number of carbon atoms present in a signature, if a signature written by carbon pencil weighs $1.2 \times 10^{- 3}$ g is:

The correct option is B
Atomic weight of Carbon = 12 g

12 g of carbon contain $6.023 \times 10^{23}$ number of atoms.

No. of carbon atoms present in $1.2 \times 10^{- 3}$ g of carbon = $\frac{1.2 \times 10^{- 3}}{12}$ $\times 6.023 \times 10^{23}$ = $\times 6.023 \times 10^{19}$