The number of chain isomers possible for hydrocarbon $C_{5} H_{12}$ is :

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Solution

The correct option is A 3
Answer:- (A) 3

$C_{5} H_{12} : C H_{3} C H_{2} C H_{2} C H_{2} C H_{3}$

$C H_{3} - C | H C H_{3} - C H_{2} - C H_{3}$ $C H_{3} - C H_{3} | C | C H_{3} - C H_{3}$

2- Methylbutane(iso-pentane), 2,2-Dimethylpropane (neo-pentane)

Thus, Isomers of $C_{5} H_{12} \Rightarrow$
(a) Pentane
(b) Iso-pentane or 2-methylbutane
(c) neo-pentane or 2,2-dimethylpropane

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Similar questions

C_{5} H_{12}

Number of chain isomer of $C_{5} H_{12}$ is :

The number of isomers formed by the hydrocarbon with molecular formular $C_{5} H_{12}$ is :
(a) 2 (b) 5 (c) 3 (d) 4

C_{4} H_{6}

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