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Question

The number of chiral carbon atoms present in open chain forms of glucose and fructose are:

A
3 in each
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B
4 in each
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C
3 in glucose 4 in fructose
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D
4 in glucose and 3 in fructose
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Solution

The correct option is D 4 in glucose and 3 in fructose
4 in glucose: Except the terminal carbon atoms, the others are all chiral.
In fructose, carbons numbered 1,2, and 6 are achiral. So 3 chiral centers.

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