Question

The number of chloride ion(s) produced by complex tetraamminedichloroplatinum(IV) chloride in an aqueous solution is

• A. Four
• B. Two
• C. Three
• D. One

Answer 1

The correct option is B Two

Formula of the complex compound is $\left[{\text{PtCl}}_2\right({\text{NH}}_3{)}_4]{\text{Cl}}_2$.
$\left[{\text{PtCl}}_2\right({\text{NH}}_3{)}_4\left]{\text{Cl}}_2\stackrel{aq}{\to }\right[{\text{PtCl}}_2({\text{NH}}_3{)}_4{]}^{2+}+2{\text{Cl}}^{-}$
Ions formed: $\left[{\text{PtCl}}_2\right({\text{NH}}_3{)}_4{]}^{2+}+2{\text{Cl}}^{-}$
Thus the number of chloride ions produced by the complex in an aqueous solution is two.