Question

The number of chocolates bought by Alex is $\frac{1}{4}$ of the number of sweets he bought. He gave 4 chocolates and 3 sweets to each of his friends, after which he had 10 chocolates and 79 sweets left. How many sweets did Alex buy?

• A. 118
• B. 150
• C. 120
• D. 88

Answer 1

The correct option is D 88

Let's suppose Alex gave chocolates and sweets to $n$ friends.

Given that, Alex has given 4 chocolates to each of his friends.
$\Rightarrow$ Total number of chocolates that Alex has given to his friends $=4\times n=4n$
After giving chocolates to his friends, Alex had 10 chocolates left.
$\Rightarrow$ Total number of chocolates that Alex bought $=4n+10$

Now,
Given that, Alex has given 3 sweets to each of his friends.
$\Rightarrow$ Total number of sweets that Alex has given to his friends $=3\times n=3n$
After distributing, Alex had 79 sweets left.
$\Rightarrow$ Total number of sweets that Alex bought $=3n+79$

Also, Alex bought $\frac{1}{4}$ as many chocolates as sweets.
$\Rightarrow 4n+10=\frac{1}{4}\times [3n+79]\Rightarrow 4\times (4n+10)=3n+79\Rightarrow 16n+40=3n+79\Rightarrow 16n-3n=79-40\Rightarrow 13n=39\Rightarrow n=3$

So, Total number of sweets that Alex bought $=3n+79=3\times 3+79=88[n=3]$

Hence, option d is correct.