The number of chromosomes involved in double fertilisation of a maize plant are = ?
Given that the diploid chromosome number of maize is 20.
50
Total diploid set of chromosomes in Maize plant is 20. During gamete formation the number becomes 10 on meiotic division. Therefore, the male gametes and the cells of the embryo sac will have chromosome number 10. Since, two haploid sperms, one haploid egg and a diploid polar nuclei is involved in double fertilisation, the number of chromosomes involved in double fertilisation in maize will be 10 +10 +10 +20 = 50.